RCC Structures Design For a continuous floor slab supported on beams, the ratio of end span length and intermediate span length, is 0.7 0.8 0.9 0.6 0.7 0.8 0.9 0.6 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 1343, total shrinkage for a pre-tensioned beam, is 3.5 × 10⁻⁵ 3.0 × 10⁻⁵ 3.0 × 10⁻² 3.0 × 10⁻³ 3.5 × 10⁻⁵ 3.0 × 10⁻⁵ 3.0 × 10⁻² 3.0 × 10⁻³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a pre-stressed member it is advisable to use High strength concrete only High strength concrete and high tensile steel Low strength concrete only Low strength concrete but high tensile steel High strength concrete only High strength concrete and high tensile steel Low strength concrete only Low strength concrete but high tensile steel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Ac, Asc and A are areas of concrete, longitudinal steel and section of a R.C.C. column and m and σc are the modular ratio and maximum stress in the configuration of concrete, the strength of column is σcAc + m σcAsc All listed here σc(A - Asc) + m σcAsc σc[A + (m - 1)Asc] σcAc + m σcAsc All listed here σc(A - Asc) + m σcAsc σc[A + (m - 1)Asc] ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are tread and rise respectively of a stair, then R + 2T= 30 2R + T = 30 2R + T = 60 R + 2T = 60 R + 2T= 30 2R + T = 30 2R + T = 60 R + 2T = 60 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS