RCC Structures Design For a continuous floor slab supported on beams, the ratio of end span length and intermediate span length, is 0.9 0.6 0.8 0.7 0.9 0.6 0.8 0.7 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In testing a pile by load test, pile platform is loaded with one and half times the design load and a maximum settlement is noted. The load is gradually removed and the consequent rebound is measured. For a safe pile, the net settlement (i.e. total settlement minus rebound) per tonne of test load should not exceed 10 mm 15 mm 25 mm 20 mm 10 mm 15 mm 25 mm 20 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the bearing capacity of soil is 10 tonnes/cm² and the projection of plain concrete footing from walls, is a cm, the depth D of footing is D = 0.775 a D = 0.775 a² D = 0.0775 a D = 0.775 √a D = 0.775 a D = 0.775 a² D = 0.0775 a D = 0.775 √a ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the diameter of the main reinforcement in a slab is 16 mm, the concrete cover to main bars is 10 mm 14 mm 12 mm 16 mm 10 mm 14 mm 12 mm 16 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The maximum shear stress (q) in concrete of a reinforced cement concrete beam is (Shear force × Width)/Lever arm Lever arm/(Shear force × Width) Width/(Lever arm × Shear force) Shear force/(Lever arm × Width) (Shear force × Width)/Lever arm Lever arm/(Shear force × Width) Width/(Lever arm × Shear force) Shear force/(Lever arm × Width) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) ANSWER DOWNLOAD EXAMIANS APP
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