MGVCL Exam Paper (30-07-2021 Shift 3) Find the word which is correctly spelt from the given options. Dimnished Profitable Clasification Idantical Dimnished Profitable Clasification Idantical ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Data Encryption Standard (DES) was designed by IBM Microsoft Apple None of these IBM Microsoft Apple None of these ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Match the following shown in table A = (iii), B = (ii), C = (i) A = (iii), B = (i), C = (ii) A = (ii), B = (i), C = (iii) A = (ii), B = (iii), C = (i) A = (iii), B = (ii), C = (i) A = (iii), B = (i), C = (ii) A = (ii), B = (i), C = (iii) A = (ii), B = (iii), C = (i) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Bus Type - Known Parameter - Unknown ParameterLoad Bus -P, Q - V, phase angleGenerator Bus - P, V (magnitude) - Q, Voltage phase angleSlack Bus Voltage - magnitude and phase angle - P, Q
MGVCL Exam Paper (30-07-2021 Shift 3) A 10-pole induction motor is supplied by a 6-pole alternator, which is driven at 1400 rpm. If the motor runs with a slip of 5%, what is its speed? 882 rpm 1575 rpm 1425 rpm 798 rpm 882 rpm 1575 rpm 1425 rpm 798 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Slip of the induction motor,S = (Ns - Nr)/NsNs = (120*f)/PPoles (P) = 61400 = (120*f)/6f = 70 HzFor P = 10Ns = (120*70)/10= 840 rpmNr = Ns(1 - S)= 840*(1 - 0.05)= 798 rpm
MGVCL Exam Paper (30-07-2021 Shift 3) મેં મીઠાઈ બનાવી'. વાક્યને કેવળ ક્રિયાપદની પ્રેરક રચના કઈ છે? મેં મીઠાઈ બનાવડાવી. મેં મીઠાઈ બનાવી લીધી. મીઠાઈ તો હું જ બનવું ને! હું મીઠાઈ બનાવવા લાગી. મેં મીઠાઈ બનાવડાવી. મેં મીઠાઈ બનાવી લીધી. મીઠાઈ તો હું જ બનવું ને! હું મીઠાઈ બનાવવા લાગી. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 20 Ω and the resistance of the resistor connected to the sound core was 40 Ω. Calculate the distance of the fault point from the test end. 100 m 200 m 300 m 400 m 100 m 200 m 300 m 400 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (20/60)*600= 200 m.
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