MGVCL Exam Paper (30-07-2021 Shift 3) દ્રશ્ય' શબ્દનો વિરુદ્ધાર્થ શબ્દ આપેલો વિકલ્પોમાંથી કયો છે? દ્રષ્ટિ દ્રશ્યમાન અદ્રશ્ય દ્રષ્ટિવંત દ્રષ્ટિ દ્રશ્યમાન અદ્રશ્ય દ્રષ્ટિવંત ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) If the phase velocity of a plane wave in a perfect dielectric is 0.4 times its value in free space, then what is the relative permittivity of the dielectric? 4.25 6.25 1.25 2.5 4.25 6.25 1.25 2.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The equation is given by:Vp (Phase velocity) = (Velocity of light in free space/Phase velocity)²= (1/0.4)²= 6.25
MGVCL Exam Paper (30-07-2021 Shift 3) હું અહી આવી શકું' વાક્યને સ્થળવાચક ક્રીયાવીશેષણમાં ફેરવો. હું નિયમિત રીતે અહી આવી શકું. હું કદી પણ નહિ આવી શકું. હું આજે નહિ આવી શકું. હું ચેન્નાઈ નહિ આવી શકું. હું નિયમિત રીતે અહી આવી શકું. હું કદી પણ નહિ આવી શકું. હું આજે નહિ આવી શકું. હું ચેન્નાઈ નહિ આવી શકું. ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A group of computers and other devices connected together is called a network and the concept of connected computers sharing resources is called ____ Routing Linking Networking Switching Routing Linking Networking Switching ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) A 50 Hz synchronous generator is connected to an infinite bus through a line. The p.u. reactances of generator and the line are j0.4 p.u. and j0.2 p.u. respectively. The generator no load voltage is 1.1 p.u. and that of infinite bus is 1.0 p.u. The inertia constant of the generator is 4 MW-sec/MVA. Determine the frequency of natural oscillations if the generator is loaded to 60% of its maximum power transfer capacity and small perturbation in power is given. 1.8 Hz 1.2 Hz 0.8 Hz 1.6 Hz 1.8 Hz 1.2 Hz 0.8 Hz 1.6 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Frequency of natural oscillation is given by,fn = {((dPe/dδ)at(δo))/M)}dPe/dδ = ((V1*V2)/X*(cosδ))= (1.1/0.6)*cosδ= (1.1/0.6)*0.5= 0.91M = (H*s)/(πf)= 4/(50π)fn = (0..91/(4/50π))= 8.9 rad/sec= 1.2 Hz
MGVCL Exam Paper (30-07-2021 Shift 3) The sending end and receiving end voltages of the short transmission line are 150 kV and 120 kV respectively. Calculate its percentage voltage regulation. 30% 40% 20% 25% 30% 40% 20% 25% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,Vs - sending end voltage in kVVr - Receiving end voltage in kV.Voltage regulation = (Vs - Vr)/Vr= (150 - 120)/120= 0.25% R = 25 %
EXAMIANS