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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respectively.

3002
3013
3024
3036

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

116
112
121
123

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number?

101
113
107
103

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is:

1600
3600
6400
14400

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag

8 : 27 : 12 hrs.
7 : 27 : 12 hrs.
6 : 27 : 12 hrs.
5 : 27 : 12 hrs.

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:

345
322
299
276

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, the numbers are (23 x 13) and (23 x 14). Larger number = (23 x 14) = 322.

MORE MCQ ON Problems on H.C.F and L.C.M

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