Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 110 360 180 420 110 360 180 420 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: 408 208 508 308 408 208 508 308 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = (11 x 7700/275) = 308.
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 16 19 18 17 16 19 18 17 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M There are four prime numbers written in ascending order of magnitude. The product of the first three is 7429 and of the last three is 12673. Find the fourth number? 31 17 29 23 31 17 29 23 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder? 1773 1245 1683 1650 1773 1245 1683 1650 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when increased by 5 is divisible by each one of 24, 32, 36 and 54, is 4320 427 859 869 4320 427 859 869 ANSWER DOWNLOAD EXAMIANS APP
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