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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

110
180
420
360

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420

Problems on H.C.F and L.C.M
Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .

4683
1683
3683
2683

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 5,6,7,8 = 840.    Required number is of the form 840k + 3     Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683

Problems on H.C.F and L.C.M
Find the least multiple of 23, which when divided by 18, 21 and 24 leaves remainders 7, 10 and 13 respectively.

3024
3013
3002
3036

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case.

52
35
48
22

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number =  H.C.F. of (132 - 62), (237 - 132) and (237 - 62)                                      =  H.C.F. of 70, 105 and 175 = 35.

Problems on H.C.F and L.C.M
The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is

110
77
88
99

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

689
268
432
1015

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015

MORE MCQ ON Problems on H.C.F and L.C.M

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