Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 110 180 420 360 110 180 420 360 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M Find the least number which when divided by 26, 36 and 46 leaves the remainders 12, 22 and 32 respectively. 10570 10750 10075 17050 10570 10750 10075 17050 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder? 5054 5073 5016 5035 5054 5073 5016 5035 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder? 1773 1650 1683 1245 1773 1650 1683 1245 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are 12, 24, 36 10, 20, 30 5, 10, 15 4, 8, 12 12, 24, 36 10, 20, 30 5, 10, 15 4, 8, 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 548 216 389 443 548 216 389 443 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.