Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 360 420 180 110 360 420 180 110 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1075 1095 1080 1085 1075 1095 1080 1085 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number? 101 113 107 103 101 113 107 103 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: 308 408 208 508 308 408 208 508 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other number = (11 x 7700/275) = 308.
Problems on H.C.F and L.C.M The H.C.F of 2923 and 3239 is : 79 37 47 73 79 37 47 73 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 46 minutes and 12 seconds 45 minutes 42 minutes and 36 seconds 26 minutes and 18 seconds 46 minutes and 12 seconds 45 minutes 42 minutes and 36 seconds 26 minutes and 18 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
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