Process Equipment and Plant Design Factor of safety (i.e., overdesign factor) in heat transfer equipments is about __________ percent more than the actual/theoretical design factor. 43961 35-40 30-35 15-20 43961 35-40 30-35 15-20 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design If a single tube pass heat exchanger is converted to two passes; for the same flow rate, the pressure drop per unit length in tube side will __________ times. None of these Increase by 21.6 Decrease by 22 Increase by 1.8 None of these Increase by 21.6 Decrease by 22 Increase by 1.8 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Lap joints are preferred for plates having thickness __________ mm. 43961 > 5 < 12.5 > 3 43961 > 5 < 12.5 > 3 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design In the case of a shell and tube heat exchanger, the logarithmic mean temperature difference Is always less than arithmetic mean value, but more than geometric mean value May be either more or less than geometric mean and arithmetic mean value depending upon whether the flow of stream is co-current or counter-current Is always less than arithmetic average value Is always more than arithmetic mean value and the geometric mean value Is always less than arithmetic mean value, but more than geometric mean value May be either more or less than geometric mean and arithmetic mean value depending upon whether the flow of stream is co-current or counter-current Is always less than arithmetic average value Is always more than arithmetic mean value and the geometric mean value ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Theoretically calculated diameter of the stripping section of the continuous rectification column is __________ that of the enriching section. Less than Same as More than Either more or less (depending upon relative volatility) Less than Same as More than Either more or less (depending upon relative volatility) ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Friction factor for turbulent flow in a new pipe is given by f = 25/NRe f = 16/NRe f = 0.22 NRe0.05 f = 0.04/NRe0.16 f = 25/NRe f = 16/NRe f = 0.22 NRe0.05 f = 0.04/NRe0.16 ANSWER DOWNLOAD EXAMIANS APP
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