RCC Structures Design Design of R.C.C. simply supported beams carrying U.D.L. is based on the resultant B.M. at Quarter span Supports Mid span Every section Quarter span Supports Mid span Every section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design To ensure that the hogging bending moment at two points of suspension of a pile of length L equals the sagging moment at its centre, the distances of the points of suspension from either end, is 0.107 L 0.207 L 0.407 L 0.307 L 0.107 L 0.207 L 0.407 L 0.307 L ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is K/x (1 + x/d) + bw Kx (1 - x/l) + bw All listed here Kx (1 + x/l) + bw K/x (1 + x/d) + bw Kx (1 - x/l) + bw All listed here Kx (1 + x/l) + bw ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress All listed here Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Long and short spans of a two way slab are ly and lx and load on the slab acting on strips parallel to lx and ly be wx and wy respectively. According to Rankine Grashoff theory (wx/wy) = (ly/lx)² (wx/wy) = (ly/lx) None of these (wx/wy) = (ly/lx)⁴ (wx/wy) = (ly/lx)² (wx/wy) = (ly/lx) None of these (wx/wy) = (ly/lx)⁴ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond length is given by π ft .d²/fb ft .d/4fb (π/4). (ft .d3/fb) (π/4). (ft .d/fb) π ft .d²/fb ft .d/4fb (π/4). (ft .d3/fb) (π/4). (ft .d/fb) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS