RCC Structures Design Design of R.C.C. simply supported beams carrying U.D.L. is based on the resultant B.M. at Quarter span Supports Every section Mid span Quarter span Supports Every section Mid span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Pick up the true statement from the following: Plain ceiling provides the best property diffusing light In the absence of beams, it is easier to install piping In the absence of beams, it is easier to paint All listed here Plain ceiling provides the best property diffusing light In the absence of beams, it is easier to install piping In the absence of beams, it is easier to paint All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a simply supported slab, alternate bars are curtailed at 1/5th of the span 1/7th of the span 1/6th of the span 1/4th of the span 1/5th of the span 1/7th of the span 1/6th of the span 1/4th of the span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘W’ is the uniformly distributed load on a circular slab of radius ‘R’ fixed at its ends, the maximum positive radial moment at its centre, is WR²/16 None of these 3WR²/16 2WR²/16 WR²/16 None of these 3WR²/16 2WR²/16 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress All listed here Removal of cracks in the members due to shrinkage Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress All listed here ANSWER DOWNLOAD EXAMIANS APP
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