RCC Structures Design Design of R.C.C. simply supported beams carrying U.D.L. is based on the resultant B.M. at Quarter span Mid span Every section Supports Quarter span Mid span Every section Supports ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t (t + c)/n = (d + n)/n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are the tread and rise of a stair which carries a load w per square metre on slope, the corresponding load per square metre of the horizontal area, is w √(R + T)/T w (R/T) w (R + T)/T w √(R² + T²)/T w √(R + T)/T w (R/T) w (R + T)/T w √(R² + T²)/T ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The maximum diameter of a bar used in a ribbed slab, is 22 mm 12 mm 20 mm 6 mm 22 mm 12 mm 20 mm 6 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The modular ratio ‘m’ of a concrete whose permissible compressive stress is ‘C’, may be obtained from the equation. m = 2800/3C m = 700/3C m = 3500/3C m = 1400/3C m = 2800/3C m = 700/3C m = 3500/3C m = 1400/3C ANSWER DOWNLOAD EXAMIANS APP
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