RCC Structures Design Design of R.C.C. simply supported beams carrying U.D.L. is based on the resultant B.M. at Supports Mid span Quarter span Every section Supports Mid span Quarter span Every section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The minimum head room over a stair must be 210 cm 205 cm 200 cm 230 cm 210 cm 205 cm 200 cm 230 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The reinforced concrete beam which has width 25 cm, lever arm 40 cm, shear force 6t/cm², safe shear stress 5 kg/cm² and B.M. 24 mt, Needs redesigning Is over safe in shear Is safe in shear Is unsafe in shear Needs redesigning Is over safe in shear Is safe in shear Is unsafe in shear ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Ac, Asc and A are areas of concrete, longitudinal steel and section of a R.C.C. column and m and σc are the modular ratio and maximum stress in the configuration of concrete, the strength of column is σcAc + m σcAsc σc[A + (m - 1)Asc] σc(A - Asc) + m σcAsc All listed here σcAc + m σcAsc σc[A + (m - 1)Asc] σc(A - Asc) + m σcAsc All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq ANSWER DOWNLOAD EXAMIANS APP