MGVCL Exam Paper (30-07-2021 Shift 3)
Consider a solar PV plant with the following specific conditions: Analysis period: 1 year Measured average solar irradiation intensity in 1 year: 150 kWh/m² Generator area of the PV plant: 10 m² Efficiency factor of the PV modules: 15% Electrical energy actually exported by plant to grid: 135 kWh Calculate the performance ratio.
After closing switch, Capacitor is behave as short circuit element, So, I(to) = V/R = 10/5 2 At t = infinite time capacitor is behave as open circuit, I(t) = I(to)e^(-t/Ƭ) Ƭ = time constant of circuit Ƭ = R*C = 200 μF I(t) = 5*e^(-t/(500*10^(-6)) = 5*e^(-5000t) A
Bus Type - Known Parameter - Unknown Parameter Load Bus -P, Q - V, phase angle Generator Bus - P, V (magnitude) - Q, Voltage phase angle Slack Bus Voltage - magnitude and phase angle - P, Q
Value of power factor is varies from 0 to 1. R→PF = 1 L→PF = 0 lag C→PF = 0 lead R-L→0 lag < PF < 1 R-C→0 lead < PF < 1 R-C-L→depends on value of R, L and C. PF = R/Z
EXAMIANS