Electrical Machines Belt conveyors offer _______________ starting torque. low. high. medium. zero. low. high. medium. zero. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a 3 - Φ induction motor power factor at starting in the same as that while running. power factor at starting is high as compared to that while running. none of them. power factor at starting is low as compared to that while running. power factor at starting in the same as that while running. power factor at starting is high as compared to that while running. none of them. power factor at starting is low as compared to that while running. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines An alternator is feeding an infinite busbar. Its prime mover is suddenly shutdown. The alternator will continue to work as synchronous motor with same direction of rotation. start working as induction motor. continue to work as alternator but the direction of rotation will reverse. come to stand still. continue to work as synchronous motor with same direction of rotation. start working as induction motor. continue to work as alternator but the direction of rotation will reverse. come to stand still. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a resistance split phase motor, what is the range of torque angle? 0° 25° to 30° 70° to 85° 90° 0° 25° to 30° 70° to 85° 90° ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines What is the necessity of copper brushes in a dc motors? To convert alternating supply current to direct current. To absorb the mechanical shocks produced during running condition. None of these. To increase the flux cutting by the rotor. To convert alternating supply current to direct current. To absorb the mechanical shocks produced during running condition. None of these. To increase the flux cutting by the rotor. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a 3 - Φ IM with line frequency f1 and winding factor kw1 and kw2 for stator and rotor respectively the ratio of per phase stator winding emf E1 to per phase rotor winding emf E2 at standstill is given by E1 / E2 = N1kw1 / N2kw2. E1 / E2 = N1 / N2. E1 / E2 = 1. E1 / E2 = f1kw1 / f2kw2. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = N1 / N2. E1 / E2 = 1. E1 / E2 = f1kw1 / f2kw2. ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS