MGVCL Exam Paper (30-07-2021 Shift 3) Arjuna Award is awarded for the excellence in which field? Mathematics Science Sports Literature Mathematics Science Sports Literature ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Replace the braketed phrase grammatically and conceptually with the help of the given opation. If the given sentence is correct then select the option ’The given sentence is correct’.The corono virus continued to spread, with the development of infections advancing quickly continue to spread, with the development of infections continued to spreading, with the development of infections continued for spread, with the development of infections The given sentence is correct continue to spread, with the development of infections continued to spreading, with the development of infections continued for spread, with the development of infections The given sentence is correct ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) સારું:નરસું::શુક્લ: ? અવિશાની કૃષ્ણ અમર પરમ અવિશાની કૃષ્ણ અમર પરમ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) Arunachal Pradesh does not share its borders with which one of the following nations? China Bhutan Myanmar Bangladesh China Bhutan Myanmar Bangladesh ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 3) The maximum value of power factor is ____ and it exists in a pure____ circuit. 0.866, resistive 1, resistive 0.866, inductive 1, inductive 0.866, resistive 1, resistive 0.866, inductive 1, inductive ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Value of power factor is varies from 0 to 1.R→PF = 1L→PF = 0 lagC→PF = 0 leadR-L→0 lag < PF < 1R-C→0 lead < PF < 1R-C-L→depends on value of R, L and C. PF = R/Z
MGVCL Exam Paper (30-07-2021 Shift 3) A 10-pole induction motor is supplied by a 6-pole alternator, which is driven at 1400 rpm. If the motor runs with a slip of 5%, what is its speed? 882 rpm 1575 rpm 1425 rpm 798 rpm 882 rpm 1575 rpm 1425 rpm 798 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Slip of the induction motor,S = (Ns - Nr)/NsNs = (120*f)/PPoles (P) = 61400 = (120*f)/6f = 70 HzFor P = 10Ns = (120*70)/10= 840 rpmNr = Ns(1 - S)= 840*(1 - 0.05)= 798 rpm
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