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MGVCL Exam Paper (30-07-2021 Shift 3)

MGVCL Exam Paper (30-07-2021 Shift 3)
Arjuna Award is awarded for the excellence in which field?

Mathematics
Literature
Science
Sports

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
Thermopile is used for the measurement of

current
flow rate
emf
temperature

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The function of a thermopile is to transfer the heat radiation emitted from the object to a voltage output.
The output is in the range of tens or hundreds of millivolts.
Thermopiles are used to provide an output in response to temperature as part of a temperature measuring device

MGVCL Exam Paper (30-07-2021 Shift 3)
A three phase four pole 50 Hz induction motor has a rotor resistance of 0.02 Ω/phase and stand-still reactance of 0.5 Ω/phase. Calculate the speed at which the maximum torque is developed.

1525 rpm
1475 rpm
1440 rpm
1500 rpm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Condition for maximum torque,
Sm = R2/X2
= 0.04
Ns = (120*f)/P
= (120*50)/4
= 1500 rpm
S = (Ns - Nr)/Ns
Nr = Ns(1 - Sm)
= 1500*(1 - 0.04)
= 1440 rpm

MGVCL Exam Paper (30-07-2021 Shift 3)
A DC shunt generator has an induced voltage of 220 V on open circuit. When the machine is on load the terminal voltage is 200 V. Find the load current if the field resistance is 100 Ω and armature resistance is 0.2 Ω.

96 A
98 A
104 A
102 A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Voltage equation for Dc shunt generator,
Eb = V + Ia*Ra
V = Ish*Rsh
Ish = 200/100
= 2 A
Eb = V + Ia*Ra
20 = Ia*Ra
Ia = 20/0.2
= 100 A
I = 100 - 2
= 98 A

MGVCL Exam Paper (30-07-2021 Shift 3)
નીચે પૈકી 'ઓસોડ' નો સમાનર્થી શબ્દ કયો છે?

અમર
ઔષધ
વૃંદા
અનરવું

ANSWER DOWNLOAD EXAMIANS APP

MGVCL Exam Paper (30-07-2021 Shift 3)
The current in the coil of a large electromagnet falls from 6 A to 2 A in 10 ms. The induced emf across the coil is 100 V. Find the self-inductance of the coil.

0.25 H
0.75 H
1.25 H
0.5 H

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Equation of self inductance:
V = Ls*(di/dt)
Ls = V/(di/dt)
= 100/((6 - 2)/(0.01))
= 0.250 H
= 250 mH

MORE MCQ ON MGVCL Exam Paper (30-07-2021 Shift 3)

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