Applied Mechanics and Graphic Statics The resultant of the forces acting on a body will be zero if the body Moves with variable velocity in a straight line Does not move at all Rotates Moves along a curved path Moves with variable velocity in a straight line Does not move at all Rotates Moves along a curved path ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The beam shown in below figure is supported by a hinge at ‘A’ and a roller at ‘B’. The reaction RA of the hinged support ‘A’ of the beam, is Applied Mechanics and Graphic Statics mcq question image 10.4 t 10.2 t 10.6 t 10.8 t 10.4 t 10.2 t 10.6 t 10.8 t ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For a body moving with simple harmonic motion, the number of cycles per second, is known as its Amplitude Frequency Oscillation Periodic time Amplitude Frequency Oscillation Periodic time ANSWER DOWNLOAD EXAMIANS APP
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