Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The intrinsic equation of catenary is y = c cosh x/c y = c cosh ψ S = c tan ψ y = c sinh ψ y = c cosh x/c y = c cosh ψ S = c tan ψ y = c sinh ψ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces acting at right angles is 5 kgf and if they act at an angle of 60°, it is 37 kgf. The magnitudes of the forces are: 3 kgf, 4 kgf 5 kgf, 3 kgf 2 kgf, 3 kgf 4 kgf, 5 kgf 3 kgf, 4 kgf 5 kgf, 3 kgf 2 kgf, 3 kgf 4 kgf, 5 kgf ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The acceleration of a train starting from rest at any instant is 1/6(V + 1) m/sec² where ‘V’ is the velocity of the train in m/sec. The train will attain a velocity of 36 km/hour after travelling a distance of 2300 m 2000 m 2100 m 2200 m 2300 m 2000 m 2100 m 2200 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A Seconds pendulum executes 1.0 beat per second 2.5 beats per second 0.5 beat per second 2.0 beats per second 1.0 beat per second 2.5 beats per second 0.5 beat per second 2.0 beats per second ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The length of a Second's pendulum, is 101 cm 99.4 cm 100 cm 99.0 cm 101 cm 99.4 cm 100 cm 99.0 cm ANSWER DOWNLOAD EXAMIANS APP
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