Theory of Machine Angular acceleration of a link can be determined by dividing the All of these Centripetal component of acceleration with length of link Resultant acceleration with length of link Tangential component of acceleration with length of link All of these Centripetal component of acceleration with length of link Resultant acceleration with length of link Tangential component of acceleration with length of link ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A shaft has an attached disc at the centre of its length. The disc has its centre of gravity located at a distance of 2 mm from the axis of the shaft. When the shaft is allowed to vibrate in its natural bow-shaped mode, it has a frequency of vibration of 10 rad/s. When the shaft is rotated at 300 r.p.m., it will whirl with a radius of 2.50 mm 2.22 mm 2 mm 3.0 mm 2.50 mm 2.22 mm 2 mm 3.0 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A combination of kinematic pairs, joined in such a way that the relative motion between the links is completely constrained, is called a Inversion Mechanism Structure Kinematic chain Inversion Mechanism Structure Kinematic chain ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The C.G. of a link in any mechanism would experience Angular acceleration No acceleration Both angular and linear accelerations Linear acceleration Angular acceleration No acceleration Both angular and linear accelerations Linear acceleration ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a truncated conical pivot bearing, considering uniform pressure, is (2/3). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3). μ W cosecα (r₁ + r₂) (1/2). μ W cosecα (r₁ + r₂) (1/2). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3). μ W cosecα (r₁ + r₂) (1/2). μ W cosecα (r₁ + r₂) (1/2). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a truncated conical pivot bearing, considering uniform wear, is (1/2). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3).μ W cosec α (r₁ + r₂) (1/2). μ W cosec α (r₁ + r₂) (2/3). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3).μ W cosec α (r₁ + r₂) (1/2). μ W cosec α (r₁ + r₂) (2/3). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] ANSWER DOWNLOAD EXAMIANS APP
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