MGVCL Exam Paper (30-07-2021 Shift 1) An RLC series circuit consists of R = 16 Ω, L = 5 mH and C = 2 μF. Calculate the quality factor. 2.125 4.125 5.125 3.125 2.125 4.125 5.125 3.125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For series RLC circuit,Q = (1/R)*√(L/C)Q = 1/16*√(5 mH/2 μF)Q = 50/16Q = 3.125
MGVCL Exam Paper (30-07-2021 Shift 1) Who has won the ‘World Games Athlete Of the Year 2019’ ? Marina Chernova Rani Rampal Rhea Stinn Stanislav Horuna Marina Chernova Rani Rampal Rhea Stinn Stanislav Horuna ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Match the following A = (iii), B = (ii), C = (i) A = (ii), B = (i), C = (iii) A = (ii), B = (iii), C = (i) A = (iii), B = (i), C = (ii) A = (iii), B = (ii), C = (i) A = (ii), B = (i), C = (iii) A = (ii), B = (iii), C = (i) A = (iii), B = (i), C = (ii) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Bus Type - Known Parameter - Unknown ParameterLoad Bus -P, Q - V, phase angleGenerator Bus - P, V (magnitude) - Q, Voltage phase angleSlack Bus Voltage - magnitude and phase angle - P, Q
MGVCL Exam Paper (30-07-2021 Shift 1) માણસ: ઘર :: પશુ : આકાશ ગુફા અંતરિક્ષ પાતાળ આકાશ ગુફા અંતરિક્ષ પાતાળ ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A fully controlled natural commutated 3-phase bridge rectifier is operating with a firing angle α = 30°, The peak to peak voltage ripple expressed as a ratio of the peak output dc voltage at the output of the converter bridge is 1-(√3/2) √3 -1 0.5 √3-1 1-(√3/2) √3 -1 0.5 √3-1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,φ is firing angleVoltage ripple for 3-phase bridge rectifier = cos(φ) = Cos(30)= 1/2
MGVCL Exam Paper (30-07-2021 Shift 1) A given solar cell has the following specifications:Open-circuit voltage, Voc: 0.7 VShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AIf the solar cell operates at maximum power point, calculate the efficiency. 14.70% 13.70% 12.70% 15.70% 14.70% 13.70% 12.70% 15.70% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation is given by:Efficiency = (F.F*Voc*Isc)/Pin= (0.6*3.5*0.7)/10= 0.14702% efficiency = 14.7 %
EXAMIANS