MGVCL Exam Paper (30-07-2021 Shift 1) An RLC series circuit consists of R = 16 Ω, L = 5 mH and C = 2 μF. Calculate the quality factor. 3.125 5.125 4.125 2.125 3.125 5.125 4.125 2.125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For series RLC circuit,Q = (1/R)*√(L/C)Q = 1/16*√(5 mH/2 μF)Q = 50/16Q = 3.125
MGVCL Exam Paper (30-07-2021 Shift 1) For protection of inter-turn fault in transformer, the relays preferred are Overcurrent relay and Buchholz's relay Buchholz's relay, overcurrent relay and differential relay Buchholz's relay and differential relay Overcurrent relay and differential relay Overcurrent relay and Buchholz's relay Buchholz's relay, overcurrent relay and differential relay Buchholz's relay and differential relay Overcurrent relay and differential relay ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Intern turn winding fault can be easily detect by differential protection relay.Also detect by buchholz relay (gas operated relay), cause buchholz relay is used to detect the internal fault of transformer.
MGVCL Exam Paper (30-07-2021 Shift 1) 1 terabyte is equal to 1024 bytes 1024 gigabytes None of these 1024 kilobytes 1024 bytes 1024 gigabytes None of these 1024 kilobytes ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Recently, India signed first ever term contract to import crude oil with which country? Japan Russia Nepal China Japan Russia Nepal China ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Fill in the blanks with suitable Preposition from the given alternatives.The match was dedicated ___ Indian fast bowler Zaheer, who has announced his retirement from international cricket from since against to from since against to ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Three resistances 750 Ω, 600 Ω and 200 Ω are connected in parallel. The total current is 1 A. Determine the voltage applied. 150 V 125 V 200 V 100 V 150 V 125 V 200 V 100 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equivalent resistance of the circuit, Req = (750|| 600 || 200)Req = 125 ΩCurrent from source = 1 ASource voltage = 1*125Source voltage = 125 V
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