MGVCL Exam Paper (30-07-2021 Shift 1) An RLC series circuit consists of R = 16 Ω, L = 5 mH and C = 2 μF. Calculate the quality factor. 2.125 5.125 4.125 3.125 2.125 5.125 4.125 3.125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For series RLC circuit,Q = (1/R)*√(L/C)Q = 1/16*√(5 mH/2 μF)Q = 50/16Q = 3.125
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 150 kW 450 kW 300 kW 600 kW 150 kW 450 kW 300 kW 600 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
MGVCL Exam Paper (30-07-2021 Shift 1) A ___ is a device that forwards packets between networks by processing the routing information included in the packet. all the mentioned above Firewall Router Bridge all the mentioned above Firewall Router Bridge ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Determine maximum permissible load which a 15 MVA, ONAN cooled transformer to IS : 2026 can take for 6 hr, if the initial load on it was 12 MVA. The weighted ambient temperature is 20˚C. Assume the permissible load kVA as a fraction of rated kVA is 1.25. 9.6 MVA 18.75 MVA 12 MVA 15 MVA 9.6 MVA 18.75 MVA 12 MVA 15 MVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Maximum permissible load = Rated MVA rating*fraction of rated kVAMaximum permissible load = 15*1.25Maximum permissible load = 18.75 MVA
MGVCL Exam Paper (30-07-2021 Shift 1) Fill in the blanks with suitable Preposition from the given alternatives.The match was dedicated ___ Indian fast bowler Zaheer, who has announced his retirement from international cricket since to against from since to against from ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) દુર્ગતિ' શબ્દનો વિરુદ્ધાર્થી શબ્દ ક્યો છે? સળંગગતિ અદુર્ગતી કુગતિ સુગતિ સળંગગતિ અદુર્ગતી કુગતિ સુગતિ ANSWER DOWNLOAD EXAMIANS APP