Hydraulics and Fluid Mechanics in ME
An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity)

tanθ = a/2g
tanθ = 2 a/g
tanθ = a2/2g
tanθ = a/g

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Hydraulics and Fluid Mechanics in ME
A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be

2A × (√H₁ - √H₂)/Cd × a × √(2g)
2A × √H₂/Cd × a × √(2g)
2A × (√H3/2 - √H3/2)/Cd × a × √(2g)
2A × √H₁/Cd × a × √(2g)

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