An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity)

• A. tanθ = 2 a/g
• B. tanθ = a2/2g
• C. tanθ = a/g
• D. tanθ = a/2g

Answer: (C)