Machine Design All stresses produced in a belt are Shear stresses Compressive stresses Tensile stresses Both tensile and compressive stresses Shear stresses Compressive stresses Tensile stresses Both tensile and compressive stresses ANSWER DOWNLOAD EXAMIANS APP
Machine Design If two springs are in parallel then their overall stiffness will be None of these Same Half Double None of these Same Half Double ANSWER DOWNLOAD EXAMIANS APP
Machine Design A steel containing 0.8% carbon is known as Hypo-eutectoid steel None of these Hypereutectoid steel Eutectoid steel Hypo-eutectoid steel None of these Hypereutectoid steel Eutectoid steel ANSWER DOWNLOAD EXAMIANS APP
Machine Design Stress concentration is caused due to Variation in properties of material from point to point in a member All of these Abrupt change of section Pitting at points or areas at which loads on a member are applied Variation in properties of material from point to point in a member All of these Abrupt change of section Pitting at points or areas at which loads on a member are applied ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design A shaft is subjected to a maximum bending stress of 80 N/mm² and maximum shearing stress equal to 30 N/mm² at a particular section. If the yield point in tension of the material is 280 N/mm² and the maximum shear stress theory of failure is used, then the factor of safety obtained will be 3.5 3.0 2.5 2.8 3.5 3.0 2.5 2.8 ANSWER DOWNLOAD EXAMIANS APP
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