Machine Design According to Indian standard specifications, a Grey cast iron designated by 'FG 200' means that the Maximum compressive strength is 200 N/mm² Maximum shear strength is 200 N/mm² Carbon content is 2% Minimum tensile strength is 200 N/mm² Maximum compressive strength is 200 N/mm² Maximum shear strength is 200 N/mm² Carbon content is 2% Minimum tensile strength is 200 N/mm² ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a hydrodynamic lubricated bearing There is a thin film of lubricant between the journal and the bearing There is a thick film of lubricant between the journal and the bearing The lubricant is forced between the journal and the bearing, by external pressure There is no lubricant between the journal and the bearing There is a thin film of lubricant between the journal and the bearing There is a thick film of lubricant between the journal and the bearing The lubricant is forced between the journal and the bearing, by external pressure There is no lubricant between the journal and the bearing ANSWER DOWNLOAD EXAMIANS APP
Machine Design Two shafts will have equal strength, if Angle of twist of both the shafts is same Twisting moment of both the shafts is same Material of both the shafts is same Diameter of both the shafts is same Angle of twist of both the shafts is same Twisting moment of both the shafts is same Material of both the shafts is same Diameter of both the shafts is same ANSWER DOWNLOAD EXAMIANS APP
Machine Design In worm, gears, pitch lead angle is None of these The angle between the tangent to the pitch helix and the plane of rotation Half the angle between two inclined faces in axial plane The angle between the tangent to the pitch helix and an element of the cylinder None of these The angle between the tangent to the pitch helix and the plane of rotation Half the angle between two inclined faces in axial plane The angle between the tangent to the pitch helix and an element of the cylinder ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design Which is positive drive? V belt drive Flat belt drive Crossed belt drive Timing belt V belt drive Flat belt drive Crossed belt drive Timing belt ANSWER DOWNLOAD EXAMIANS APP
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