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Mass Transfer

Mass Transfer
According to Poiseuille's law, the permeability for gas flow through a capillary is proportional to (where, μ = gas viscosity)

μ
μ²
√μ
1/μ

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Mass Transfer
In a single stage extraction process, 10 kg of pure solvent S (containing no solute A) is mixed with 30 kg of feed F containing A at a mass fraction xf = 0.2. The mixture splits into an extract phase E and a raf-finate phase R containing A at xB = 0.5 and xR = 0.05 respectively. The total mass of the extract phase is (in Kg)

6.89
10
8.25
8.89

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Mass Transfer
According to Chilton-Colburn analogy for mass transfer, NSt.NSc2/3 is equal to

1/f
F
F/2
2f

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Mass Transfer
Unit of molal diffusivity is

Cm²/sec gm . mole
Gm moles/cm² . sec
Gm moles/cm. sec
Gm moles/cm². sec

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Mass Transfer
For the flow of gases through a capillary, with increase in temperature, the permeability __________ as per Knudsen law.

Remains same
Either A or B; depends on the gas
Decreases
Increases

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Mass Transfer
Lewis number (Le) is

Pr x St
Sc x Pr
St x Sh
Sh x Pr

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MORE MCQ ON Mass Transfer

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