Machine Design According to I.B.R., the efficiency of a double riveted butt joint with double cover straps of equal width should be 45 to 60% 80 to 90% 70 to 83% 63 to 70% 45 to 60% 80 to 90% 70 to 83% 63 to 70% ANSWER DOWNLOAD EXAMIANS APP
Machine Design A shaft is subjected to fluctuating loads for which the normal torque (T) and bending moment (M) are 1000 N-m and 500 N-m respectively. If the combined shock and fatigue factor for bending is 1.5 and combined shock and fatigue factor for torsion is 2, then the equivalent twisting moment for the shaft is 2050 N-m 2136 N-m 2000 N-m 2100 N-m 2050 N-m 2136 N-m 2000 N-m 2100 N-m ANSWER DOWNLOAD EXAMIANS APP
Machine Design A tap bolt Has both the ends threaded Has pointed threads Has a head on one end and a nut fitted to the other Has head at one end and other end fits into a tapped hole in the other part to be joined Has both the ends threaded Has pointed threads Has a head on one end and a nut fitted to the other Has head at one end and other end fits into a tapped hole in the other part to be joined ANSWER DOWNLOAD EXAMIANS APP
Machine Design The relation between the pitch of the chain (p) and pitch circle diameter of the sprocket (D) is given by (where T = Number of teeth on the sprocket) p = D sin (360°/T) p = D sin (120°/T) p = D sin (180°/T) p = D sin (90°/T) p = D sin (360°/T) p = D sin (120°/T) p = D sin (180°/T) p = D sin (90°/T) ANSWER DOWNLOAD EXAMIANS APP
Machine Design If a bearing is designated by the number 305, it means that the bearing is of Medium series whose bore is 25 mm Light series whose bore is 5 mm Medium series whose bore is 5 mm Light series whose bore is 25 mm Medium series whose bore is 25 mm Light series whose bore is 5 mm Medium series whose bore is 5 mm Light series whose bore is 25 mm ANSWER DOWNLOAD EXAMIANS APP
Machine Design When an open coiled helical compression spring is subjected to an axial compressive load, the maximum shear stress induced in the wire is (where D = Mean diameter of the spring coil, d = Diameter of the spring wire, K = Wahl's stress factor, and W = Axial compressive load on the spring) (4WD/ πd3) × K (8WD/ πd3) × K (WD/ πd3) × K (2WD/ πd3) × K (4WD/ πd3) × K (8WD/ πd3) × K (WD/ πd3) × K (2WD/ πd3) × K ANSWER DOWNLOAD EXAMIANS APP
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