SSC JE Electrical 2019 with solution SET-1 A synchronous motor runs at 600rpm, which of the following case is true? P= 12, f = 50 Hz P = 8, f = 50 Hz P = 12, f = 60 Hz P = 10, f = 60 Hz P= 12, f = 50 Hz P = 8, f = 50 Hz P = 12, f = 60 Hz P = 10, f = 60 Hz ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Synchronous speed NS = 120f/PWhenP = 12 & F = 60 then Ns = ?NS = 120f/P = (120 × 60)/12 = 600 RPM
SSC JE Electrical 2019 with solution SET-1 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel 100 μF 1 μF 50 μF 0.1 μF 100 μF 1 μF 50 μF 0.1 μF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When the capacitance is connected in series the total capacitance is given byCeq = C1 + C2 + C3………CNCeq = 10nCeq =10 × 10 = 100 μF
SSC JE Electrical 2019 with solution SET-1 When the only current source is active in the circuit, find the current through the 10Ω resistor 1.66 A 1.33 A 0.66 A 0 A 1.66 A 1.33 A 0.66 A 0 A ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 A coil is wound with 50 turns and a current 8A produces a flux of 200μWb. Calculate the inductance of the coil 0.125 mH 1.25 mH 0.25 mH 2.5 mH 0.125 mH 1.25 mH 0.25 mH 2.5 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The inductance of the coil is given by the relationL = Nφ/IWhereN = number of turns = 50φ = flux = 200μWbI = current = 8 AL = 50 × 200 × 10−6 ⁄ 8L = 1.25 mH
SSC JE Electrical 2019 with solution SET-1 If N = linkage flux, then the linkage flux per unit current is defined as: Magnetomotive force Inductive reactance Leakage coefficient Inductance Magnetomotive force Inductive reactance Leakage coefficient Inductance ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The inductance L of this coil is defined as the flux linkage per unit current and its unit is Henry.L =Λ/IWhereΛ = Flux linkageI = current
SSC JE Electrical 2019 with solution SET-1 An electric heater is connected across 230V and it draws a current of 2A. Then the resistance offered by the heater is? 290 ohm 115 ohm 29 ohm 11.5 ohm 290 ohm 115 ohm 29 ohm 11.5 ohm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP GivenVoltage V = 230 VCurrent I = 2 AResistance R = V/IR = 230/2 = 115 Ω
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