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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 A synchronous motor runs at 600rpm, which of the following case is true?

P = 8, f = 50 Hz
P = 10, f = 60 Hz
P= 12, f = 50 Hz
P  = 12, f = 60 Hz

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Synchronous speed NS = 120f/P
When
P = 12 & F = 60 then Ns = ?
NS = 120f/P = (120 × 60)/12 = 600 RPM

SSC JE Electrical 2019 with solution SET-1
______ Opposes the change in circuit voltage

Inductive reactance
Inductance
Resistance
Capacitance

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
Hunting occurs in a/an motor

Synchronous
DC shunt
DC series
Induction

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Sudden changes of load on synchronous motors may sometimes set up oscillations that are superimposed upon the normal rotation, resulting in periodic variations of a very low frequency in speed. This effect is known as hunting or phase-swinging.
 

SSC JE Electrical 2019 with solution SET-1
  ______starting method CANNOT be used for starting a 3-phase squirrel cage induction motor

Direct-on-line
Rotor-resistance
Auto-transformer
Star-delta

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 Which of the following fuel has the least calorific value?

Kerosene oil
Wood
Hydrogen
LPG

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

In the above option, the wood has the lowest calorific value. Its value is around 17000 – 20000 kilojoule/kg.
The calorific value of LPG is 55000 kilojoule/kg.
The calorific value of Kerosene oil is 45000 kilojoule/kg.
The calorific value of hydrogen oil is 150000 kilojoule/kg.
 

SSC JE Electrical 2019 with solution SET-1
 A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is

0.4 V
−2.5 V
−4 V
−10 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given
Inductance L = 2 H
Rate of change of current di/dt = 5 A/sec
Self induced EMF = − (Rate of change of current × Inductance) = −L(di/dt)
= −(5 × 2) = −10V
 

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