Theory of Machine A shaft has two heavy rotors mounted on it. The transverse natural frequencies, considering each of the rotor separately, are 100 Hz and 200 Hz respectively. The lowest critical speed is 9,360 r.p.m. 12,000 r.p.m. 5,367 r.p.m. 6,000 r.p.m. 9,360 r.p.m. 12,000 r.p.m. 5,367 r.p.m. 6,000 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 2(l - 1) - 2j - h ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Which of the following mechanisms produces mathematically an exact straight line motion? Peaucellier's mechanism Tchebicheff mechanism Grasshopper mechanism Watt mechanism Peaucellier's mechanism Tchebicheff mechanism Grasshopper mechanism Watt mechanism ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine For an isochronous Hartnell governor (where r₁ and r₂ = Maximum and minimum radius of rotation of balls respectively, S₁ and S₂ = Maximum and minimum force exerted on the sleeve respectively, and M = Mass on the sleeve) S₁/S₂ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ (m.g + S₁)/(m.g + S₂) = r₁/r₂ S₂/S₁ = r₁/r₂ S₁/S₂ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ (m.g + S₁)/(m.g + S₂) = r₁/r₂ S₂/S₁ = r₁/r₂ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Which of the following mechanism is obtained from lower pair? Valve and valve gears Gyroscope All of these Pantograph Valve and valve gears Gyroscope All of these Pantograph ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a cam drive with uniform velocity follower, the sharp corners of the displacement diagram are rounded off at the beginning and at the end of each stroke. This is done Because of difficulty in manufacturing cam profile Because the uniform velocity motion is a partial parabolic motion In order to have acceleration in beginning and retardation at the end of stroke within the finite limits Because of loose contact of follower with cam surface Because of difficulty in manufacturing cam profile Because the uniform velocity motion is a partial parabolic motion In order to have acceleration in beginning and retardation at the end of stroke within the finite limits Because of loose contact of follower with cam surface ANSWER DOWNLOAD EXAMIANS APP
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