Theory of Machine A pulley and belt in a belt drive form a Rolling pair Turning pair Cylindrical pair Sliding pair Rolling pair Turning pair Cylindrical pair Sliding pair ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A shaft has an attached disc at the centre of its length. The disc has its centre of gravity located at a distance of 2 mm from the axis of the shaft. When the shaft is allowed to vibrate in its natural bow-shaped mode, it has a frequency of vibration of 10 rad/s. When the shaft is rotated at 300 r.p.m., it will whirl with a radius of 2.50 mm 2 mm 2.22 mm 3.0 mm 2.50 mm 2 mm 2.22 mm 3.0 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The example of successfully constrained motion is a Motion of the shaft between a footstep bearing Motion of an I.C. engine valve All of these Piston reciprocating inside an engine cylinder Motion of the shaft between a footstep bearing Motion of an I.C. engine valve All of these Piston reciprocating inside an engine cylinder ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Coriolis component of acceleration exists whenever a point moves along a path that has Linear displacement Rotational motion Tangential acceleration Gravitational acceleration Linear displacement Rotational motion Tangential acceleration Gravitational acceleration ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine One end of a helical spring is fixed while the other end carries the load W which moves with simple harmonic motion. The frequency of motion is given by (where δ = Deflection of the spring) 2π. √(δ/g) 1/2π. √(δ/g) 2π. √(g/δ) 1/2π. √(g/δ) 2π. √(δ/g) 1/2π. √(δ/g) 2π. √(g/δ) 1/2π. √(g/δ) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a band and block brake, the ratio of tensions on tight side and slack side of the band is (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the center of drum, and n = Number of blocks) T₁/T₂ = μ. θ. n T₁/T₂ = [(1 - μ tanθ)/(1 + μ tanθ)]n T₁/T₂ = (μ θ)n T₁/T₂ = [(1 + μ tanθ)/(1 - μ tanθ)]n T₁/T₂ = μ. θ. n T₁/T₂ = [(1 - μ tanθ)/(1 + μ tanθ)]n T₁/T₂ = (μ θ)n T₁/T₂ = [(1 + μ tanθ)/(1 - μ tanθ)]n ANSWER DOWNLOAD EXAMIANS APP
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