RCC Structures Design A pre-stressed concrete member is preferred because All listed here Its dimensions are not decided from the diagonal tensile stress Large size of long beams carrying large shear force need not be adopted Removal of cracks in the members due to shrinkage All listed here Its dimensions are not decided from the diagonal tensile stress Large size of long beams carrying large shear force need not be adopted Removal of cracks in the members due to shrinkage ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If permissible working stresses in steel and concrete are respectively 1400 kg/cm² and 80 kg/cm² and modular ratio is 18, in a beam reinforced in tension side and of width 30 cm and having effective depth 46 cm, the lever arms of the section, is 40 cm 38 cm 39 cm 37 cm 40 cm 38 cm 39 cm 37 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Steel beam theory is used for Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete Design of simple steel beams Doubly reinforced beams ignoring compressive stress in concrete Beams if shear exceeds 4 times allowable shear stress Steel beams encased in concrete Design of simple steel beams Doubly reinforced beams ignoring compressive stress in concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design After pre-stressing process is completed, a loss of stress is due to Shrinkage of concrete Creep of concrete Elastic shortening of concrete All of the listed here Shrinkage of concrete Creep of concrete Elastic shortening of concrete All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The design of heel slab of a retaining wall is based on the maximum bending moment due to: Its own weight All listed here Load of the surcharge, if any Weight of the soil above it Its own weight All listed here Load of the surcharge, if any Weight of the soil above it ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Bending moment × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
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