RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm², the share stirrups are provided for a distance ‘x’ from either end where, ‘x’ is 100 cm 150 cm 200 cm 50 cm 100 cm 150 cm 200 cm 50 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of a two way slab simply supported on edges and having no provision to prevent the corners from lifting, is made by Grashoff formula Marcus formula Rankine formula Rankine Grashoff formula Grashoff formula Marcus formula Rankine formula Rankine Grashoff formula ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Lapped splices in tensile reinforcement are generally not used for bars of size larger than 36 mm diameter 24 mm diameter 18 mm diameter 30 mm diameter 36 mm diameter 24 mm diameter 18 mm diameter 30 mm diameter ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pile of length ‘L’ carrying a uniformly distributed load ‘W’ per metre length is suspended at two points, the maximum, B.M. at the centre of the pile or at the points of suspension, is WL²/16 WL²/24 WL²/47 WL/8 WL²/16 WL²/24 WL²/47 WL/8 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The reinforced concrete beam which has width 25 cm, lever arm 40 cm, shear force 6t/cm², safe shear stress 5 kg/cm² and B.M. 24 mt, Needs redesigning Is over safe in shear Is unsafe in shear Is safe in shear Needs redesigning Is over safe in shear Is unsafe in shear Is safe in shear ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)² ANSWER DOWNLOAD EXAMIANS APP
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