MGVCL Exam Paper (30-07-2021 Shift 2)
A power factor less than unity results in which of the following disadvantages?
(i) Large kVA rating of equipment
(ii)Poor voltage regulation
(iii) Greater conductor size

(ii) and (iii) only
(i) and (ii) only
(i), (ii) and (iii)
(i) and (iii) only

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MGVCL Exam Paper (30-07-2021 Shift 2)
When different types of consumers are charged at different uniform per unit rates, it is called as ____

block rate tariff
two-part tariff
flat rate tariff
maximum demand tariff

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MGVCL Exam Paper (30-07-2021 Shift 2)
The necessary equation to be solved during the load flow analysis using Fast-Decoupled method is given below:
where B' and B'' are formed using the imaginary part of the bus admittance matrix, Ybus. If the system consists of 6 buses of which one of the bus is slack bus and 2 bues are voltage regulated buses, then then the matrix B' is of order ____and the matrix B'' is of order____, respectivity.
∆P/|Vi| = - B'∆δ
∆Q/|Vi| = - B''∆|V|

3 and 5
5 and 3
3 and 6
6 and 3

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MGVCL Exam Paper (30-07-2021 Shift 2)
A generating station having 'n' section busbars each rated at Q kVA with ×% reactance is connected on the tie-bars systems through busbar reactances of b%. Determine the short circuit kVA if a 3-phase fault takes place on one section.

Q[(1/x) + (n+1)/(bn-x)]
Q[(1/x) + (n+1)/(bn+x)]
Q[(1/x) - (n+1)/(bn-x)]
Q[(1/x) + (n-1)/(bn+x)]

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MGVCL Exam Paper (30-07-2021 Shift 2)
In the circuit of figure, the switch is closed to position-1 for a long time. At t = 0 the switch position is changed from postion-1 to postion-2. Find an expression for the current i(t).

i(t) = (E/R) sin√(LC) t A
i(t) = (E/R) cos√(LC) t A
i(t) = (E/R) cos[1/√(LC)]t A
i(t) = (E/R) sin[1/√(LC)]t A

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