Hydraulics and Fluid Mechanics in ME A pipe of length more than double the diameter of orifice fitted externally or internally to the orifice is called a Notch Nozzle Weir Mouthpiece Notch Nozzle Weir Mouthpiece ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The major loss of energy in long pipes is due to sudden enlargement sudden contraction gradual contraction or enlargement friction sudden enlargement sudden contraction gradual contraction or enlargement friction ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The power transmitted through the pipe is maximum when the head lost due to friction is equal to One-fourth of the total supply head Two-third of the total supply head One-half of the total supply head One-third of the total supply head One-fourth of the total supply head Two-third of the total supply head One-half of the total supply head One-third of the total supply head ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The total pressure force on a plane area is equal to the area multiplied by the intensity of pressure at the Centroid, if The area is horizontal All of these The area is vertical The area is inclined The area is horizontal All of these The area is vertical The area is inclined ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME An internal mouthpiece is said to be running free if the length of the mouthpiece is __________ the diameter of the orifice. Less than twice More than three times Less than three times More than twice Less than twice More than three times Less than three times More than twice ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a wholly drowned orifice is given by (where H1 = Height of water (on the upstream side) above the top of the orifice, H2 = Height of water (on the downstream side) above the bottom of the orifice, and H = Difference between two water levels on either side of the orifice) Q = Cd × bH₁ × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH × √(2gh) Q = Cd × bH2 × √(2gh) Q = Cd × bH₁ × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH × √(2gh) Q = Cd × bH2 × √(2gh) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS