Hydraulics and Fluid Mechanics in ME In a lock-gate, the reaction between two gates is (where P = Resultant pressure on the lock gate, and α = Inclination of the gate with the normal to the side of the lock) 2p/sin (α/2) 2p/sinα p/sinα p/2sinα 2p/sin (α/2) 2p/sinα p/sinα p/2sinα ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The Bernoulli's equation is based on the assumption that No force except gravity acts on the fluid The velocity of flow is uniform across any cross-section of the pipe There is no loss of energy of the liquid flowing All of these No force except gravity acts on the fluid The velocity of flow is uniform across any cross-section of the pipe There is no loss of energy of the liquid flowing All of these ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a channel of trapezoidal section is maximum when The sloping side is equal to the width at the bottom Depth of channel is equal to the width at the bottom Width of channel at the top is equal to twice the width at the bottom The sloping side is equal to half the width at the top The sloping side is equal to the width at the bottom Depth of channel is equal to the width at the bottom Width of channel at the top is equal to twice the width at the bottom The sloping side is equal to half the width at the top ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME High specific speed of turbine implies it is None of the listed here Francis turbine Impulse turbine Propeller turbine None of the listed here Francis turbine Impulse turbine Propeller turbine ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The Francis formula for the discharge over Cipoletti weir is 1.84 LH 1.84 LH5/2 1.84 LH1/2 1.84 LH3/2 1.84 LH 1.84 LH5/2 1.84 LH1/2 1.84 LH3/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a wholly drowned orifice is given by (where H1 = Height of water (on the upstream side) above the top of the orifice, H2 = Height of water (on the downstream side) above the bottom of the orifice, and H = Difference between two water levels on either side of the orifice) Q = Cd × bH × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH2 × √(2gh) Q = Cd × bH₁ × √(2gh) Q = Cd × bH × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH2 × √(2gh) Q = Cd × bH₁ × √(2gh) ANSWER DOWNLOAD EXAMIANS APP
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