Hydraulics and Fluid Mechanics in ME In a lock-gate, the reaction between two gates is (where P = Resultant pressure on the lock gate, and α = Inclination of the gate with the normal to the side of the lock) p/sinα 2p/sin (α/2) 2p/sinα p/2sinα p/sinα 2p/sin (α/2) 2p/sinα p/2sinα ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Coefficient of resistance is the ratio of Loss of head in the orifice to the head of water available at the exit of the orifice Actual discharge through an orifice to the theoretical discharge Area of jet at vena-contracta to the area of orifice Actual velocity of jet at vena-contracta to the theoretical velocity Loss of head in the orifice to the head of water available at the exit of the orifice Actual discharge through an orifice to the theoretical discharge Area of jet at vena-contracta to the area of orifice Actual velocity of jet at vena-contracta to the theoretical velocity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Two pipe systems can be said to be equivalent, when the following quantities are same Friction loss and flow Friction factor and diameter Flow and length Length and diameter Friction loss and flow Friction factor and diameter Flow and length Length and diameter ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME One stoke is equal to 10-6 m2/s 10-3 m2/s 10-4 m2/s 10-2 m2/s 10-6 m2/s 10-3 m2/s 10-4 m2/s 10-2 m2/s ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Which of the following pump is successfully used for lifting water to the turbines? Air lift pump Jet pump Centrifugal pump Reciprocating pump Air lift pump Jet pump Centrifugal pump Reciprocating pump ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to empty the tank completely will be (2AH₁²)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) (2AH₁3/2)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) (2AH₁²)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) (2AH₁3/2)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) ANSWER DOWNLOAD EXAMIANS APP
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