Hydraulics and Fluid Mechanics in ME In a reciprocating pump, air vessels are used to Smoothen the flow Reduce suction head Reduce acceleration head Increase delivery head Smoothen the flow Reduce suction head Reduce acceleration head Increase delivery head ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME If Hg is the gross or total head and hf is the head lost due to friction, then net or effective head (H) is given by H = Hg/hf H = Hg × hf H = Hg + hf H = Hg - hf H = Hg/hf H = Hg × hf H = Hg + hf H = Hg - hf ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to fan laws, for fans having constant wheel diameter, the air or gas capacity varies Square root of fan speed Cube of fan speed Directly as fan speed Square of fan speed Square root of fan speed Cube of fan speed Directly as fan speed Square of fan speed ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A hemispherical tank of radius (R) has an orifice of cross-sectional area (a) at its bottom and is full of liquid. The time required to empty the tank completely is 14π R7/2/15Cd × a √(2g) 14π R1/2/15Cd × a √(2g) 14π R3/2/15Cd × a √(2g) 14π R5/2/15Cd × a √(2g) 14π R7/2/15Cd × a √(2g) 14π R1/2/15Cd × a √(2g) 14π R3/2/15Cd × a √(2g) 14π R5/2/15Cd × a √(2g) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME When a liquid is flowing through a pipe, the velocity of the liquid is Zero at the centre and maximum near the walls Maximum at the centre and zero near the walls Minimum at the centre and maximum near the walls Maximum at the centre and minimum near the walls Zero at the centre and maximum near the walls Maximum at the centre and zero near the walls Minimum at the centre and maximum near the walls Maximum at the centre and minimum near the walls ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Bazin's formula, the discharge over a rectangular weir is mL2g x H3/2 where m is equal to 0.405 + (0.003/H) 0.003 + (H/0.405) 0.405 + (H/0.003) 0.003 + (0.405/H) 0.405 + (0.003/H) 0.003 + (H/0.405) 0.405 + (H/0.003) 0.003 + (0.405/H) ANSWER DOWNLOAD EXAMIANS APP
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