Problems on H.C.F and L.C.M
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?
L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.
Converting given measurements into centimeters 4m 96 cm = 400+96 = 496 cm 4m 3cm = 400+3 =403 cmTo find the side of the largest possible brick , the side of brick must divide length as well as breadth exactly. Using division method 403)496(1 403 93) 403 (4 370 31) 93 (3 93 0HCF = 31 Side of the largest possible square brick =31cm
Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
EXAMIANS