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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?

40
35
37
39

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

112
116
123
121

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is:

40
20
30
60

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Problems on H.C.F and L.C.M
Find the lowest common multiple of 24, 36 and 40.

240
480
120
360

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 2 | 24 - 36 - 40 -------------------- 2 | 12 - 18 - 20 -------------------- 2 | 6 - 9 - 10 ------------------- 3 | 3 - 9 - 5 ------------------- | 1 - 3 - 5 L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.

Problems on H.C.F and L.C.M
LCM of 87 and 145 is:

435
1305
48
875

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Product of two co-prime numbers is 117. Their L.C.M should be:

1
Cannot be calculated
F
117
equal to their H.

ANSWER DOWNLOAD EXAMIANS APP
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