Applied Mechanics and Graphic Statics A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The velocity ratio of the lifting machine is 60 50 65 55 60 50 65 55 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of Applied Mechanics and Graphic Statics mcq question image (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ladder of weight 'w' rests against a smooth vertical wall, and rests on rough horizontal ground, the coefficient of friction between the ladder and the ground being 1/4. The maximum angle of inclination of the ladder to the vertical, if a man of weight 'w' is to walk to the top of it safely, is tan'1 x, where x is 1/3 1/4 4 3 1/3 1/4 4 3 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resolved part of the resultant of two forces inclined at an angle θ in a given direction is Sum of the forces multiplied by the tangent θ° Difference of the forces multiplied by cosine θ° Arithmetical sum of the resolved parts of the forces in the direction Algebraic sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Difference of the forces multiplied by cosine θ° Arithmetical sum of the resolved parts of the forces in the direction Algebraic sum of the resolved parts of the forces in the direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The rate of change of displacement of a body with respect to its surrounding, is known Velocity Acceleration Speed None of these Velocity Acceleration Speed None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two parallel forces 20 kg and 15 kg act. In order that the distance of the resultant from 20 kg force may be the same as that of the former resultant was from 15 kg, the 20 kg force is diminished by 5.5 kg 6.25 kg 8.75 kg 10.5 kg 5.5 kg 6.25 kg 8.75 kg 10.5 kg ANSWER DOWNLOAD EXAMIANS APP
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