Applied Mechanics and Graphic Statics A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The velocity ratio of the lifting machine is 50 65 55 60 50 65 55 60 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Pick up the correct statement from the following. A rubber ball when strikes a wall rebounds but a lead ball of same mass and velocity when strikes the same wall, falls down Rubber and lead balls undergo equal changes in momentum Momentum of rubber ball is less than that of lead ball Change in momentum suffered by lead ball is less that of rubber ball None of these Rubber and lead balls undergo equal changes in momentum Momentum of rubber ball is less than that of lead ball Change in momentum suffered by lead ball is less that of rubber ball None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The motion of a particle is described by the relation x = t²- 10t + 30, where x is in meters and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be 60 m 50 m 30 m Zero 60 m 50 m 30 m Zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A system of coplanar forces acting on a rigid body can be reduced to One force and one couple only None of these One couple only One force only One force and one couple only None of these One couple only One force only ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A string of length 90 cm is fastened to two points ‘A’ and ‘B’ at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force ‘P’ is applied to the ring such that it is in equilibrium vertically below ‘B’. The value of ‘P’ is: 40 g 60 g 80 g 100 g 40 g 60 g 80 g 100 g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) ANSWER DOWNLOAD EXAMIANS APP
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