Applied Mechanics and Graphic Statics A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The efficiency of the lifting machine is 0.3 0.4 0.55 0.5 0.3 0.4 0.55 0.5 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rope is wrapped twice around a rough pole with a coefficient of friction ‘A . It is subjected to a force Fj at one end and a gradually increasing force F2 is applied at the other end till the rope just starts slip-ping. At this instant the ratio of F2 to Fi is e*72 e4* e2* 1 e*72 e4* e2* 1 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle is dropped from the top of a tower 60 m high and another is projected upwards from the foot of the tower to meet the first particle at a height of 15.9 m. The velocity of projection of the second particle is 22 m/sec 16 m/sec 18 m/sec 20 m/sec 22 m/sec 16 m/sec 18 m/sec 20 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In case of S.H.M. the period of oscillation (T), is given by T = π/2ω T = 2π/ω T = 2/ω T = 2ω/π² T = π/2ω T = 2π/ω T = 2/ω T = 2ω/π² ANSWER DOWNLOAD EXAMIANS APP
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