Irrigation Engineering A hydraulic structure is designed to withstand Hydraulic jump All of these Seepage forces Hydraulic pressure Hydraulic jump All of these Seepage forces Hydraulic pressure ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering A divide wall is provided At an inclination to the axis of weir Parallel to the axis of weir and downstream of it Parallel to the axis of weir and upstream of it At right angle to the axis of weir At an inclination to the axis of weir Parallel to the axis of weir and downstream of it Parallel to the axis of weir and upstream of it At right angle to the axis of weir ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering An aggrading river is a scouring river neither silting nor scouring river silting river both silting and scouring river scouring river neither silting nor scouring river silting river both silting and scouring river ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering The total capacity of a reservoir is 25 million cubic metres and dead storage is 5 million cubic metres. If the average volume of sediment deposition is 0.10 million cubic metre per year, then the usefulness of the reservoir will start reducing after 50 years 200 years 250 years 150 years 50 years 200 years 250 years 150 years ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering With the increase in the quantity of water supplied, the yield of most crops decreases continuously increases upto a certain limit and then becomes constant increases upto a certain limit and then decreases increases continuously decreases continuously increases upto a certain limit and then becomes constant increases upto a certain limit and then decreases increases continuously ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering If the height of the hydraulic gradient line above the floor of thickness t is h and the specific gravity of the material of the floor is G, the minimum thickness t of the floor downstream of the crest-wall, is given by the equation t = (h + 1)/(G + t) t = (h - 1)/(G + t) t = (h - 1)/(G - t) t = (h + 1)/G t = (h + 1)/(G + t) t = (h - 1)/(G + t) t = (h - 1)/(G - t) t = (h + 1)/G ANSWER DOWNLOAD EXAMIANS APP