Theory of Machine A foot step bearing and rotor of a vertical turbine form examples of Completely constrained motion Successfully constrained motion Partially constrained motion Incompletely constrained motion Completely constrained motion Successfully constrained motion Partially constrained motion Incompletely constrained motion ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 3(l - 1) - 2j - h n = 2(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 3(l - 1) - 3j - h ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In an ideal machine, the output as compared to input is Equal May be less or more depending on efficiency More Less Equal May be less or more depending on efficiency More Less ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r cosθ m.ω².r sinθ m.ω².r (cos 2θ/n) m.ω².r (sin 2θ/n) m.ω².r cosθ m.ω².r sinθ m.ω².r (cos 2θ/n) m.ω².r (sin 2θ/n) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In considering friction of a V-thread, the virtual coefficient of friction (μ₁) is given by μ₁ = μ cos β μ₁ = μ/sin β μ₁ = μ/cos β μ₁ = μ sin β μ₁ = μ cos β μ₁ = μ/sin β μ₁ = μ/cos β μ₁ = μ sin β ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A slider moves at a velocity v on a link revolving at ω rad/s. The coriolis component of acceleration is 2ωv 2ωv² ωv ω²v 2ωv 2ωv² ωv ω²v ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS