SSC JE Electrical 2019 with solution SET-2
For a three-phase induction motor slip at No Load ÷  slip at Full Load

Always equal to zero
Always equal to one
Always less than one
Always less than one

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SSC JE Electrical 2019 with solution SET-2
Observe the given figure. The maximum power to the load resistor is when Ri is  =?

4Ri
RL
Ri/2
2Ri

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SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL = Ise + Ia
IL ÷ Ise = Ia
IL = Ise = Ia
IL ÷ Ise ÷ Ia

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