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SSC JE Electrical 2019 with solution SET-2

SSC JE Electrical 2019 with solution SET-2
A coil of 360 turns is linked by a flux of 200 μWb. If the flux is reversed in 0.01 second, then find the EMF induced in the coil?

144 V
14.4 V
7.2 V
0.72 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given


SSC JE Electrical 2019 with solution SET-2
Which of the following is NOT an expression to find self-inductance?

N2/S
Nφ
Nφ/I
N2μoμrA/I

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SSC JE Electrical 2019 with solution SET-2
1 kcal is approximately equal to

420 joules
4.2 joules
4200 watt-sec
420 watt-hour

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

1 kcal = 4200 J
Watt = Joule/S
joule =  watt/sec
4200 joule = 4200 watt-sec

SSC JE Electrical 2019 with solution SET-2
Which of the following heating element has the lowest operating temperature?

Eureka
Nichrome
Kanthal
Graphite

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The melting point of Eureka is 1221 to 1300 °C
The melting point of Kanthal is 1,425 °C
The melting point of Nichrome is 1400 °C
The melting point of Graphite is 3,600°C
Hence Eureka has the least range of temperature.
 

SSC JE Electrical 2019 with solution SET-2
The change in DC excitation of a synchronous motor will also change the

Supply voltage
Power factor
Speed of the motor
Load angle

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SSC JE Electrical 2019 with solution SET-2
If ‘V’ is the voltage phasor and ‘I’ is the current phasor, then VI represents

Active power
Total power
Apparent power
Reactive power

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Apparent Power (S): It is defined as the product of r.m.s value of voltage (V) and current (1). It is denoted by S.
S = V/I Volt Ampere

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