UV Luminance Spectroscopy
Why must the radiation source for fluorescence spectrometry be more powerful than for absorption spectroscopy?

Because the magnitude of the output signal is proportional to the power of the incident radiation
To allow for scattering by the sample
None of these
Because the sample won't fluoresce if the incident radiation is of low power

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UV Luminance Spectroscopy
Internal conversion is where

A molecule converts excess electronic energy to vibrational energy
None of these
the spin of an excited electron reverses, changing the state of the molecule (from singlet state to triplet state or vice versa)
A molecule converts its excess energy to light, and emits a photon

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UV Luminance Spectroscopy
In the intersystem crossing

a molecule converts excess electronic energy to vibrational energy
a molecule converts its excess energy to light, and emits a photon
All of these
the spin of an excited electron reverses, changing the state of the molecule (from singlet state to triplet state or vice versa)

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UV Luminance Spectroscopy
For a molecule to absorb IR, why must the molecule's vibrations cause fluctuations in the dipole moment of the molecule?

Because for absorption to occur, the radiation must interact with the electric field caused by changing dipole moment
Because fluctuations in the dipole moment allow the molecule to deform by bending and stretching
All of these
Because a change in dipole moment lowers the energy required for electronic transitions

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UV Luminance Spectroscopy
Fluorescence occurs when

a molecule lowers its vibrational energy by losing it's excess energy as a photon
a molecule returns to the electronic ground state from an excited singlet state by losing it's excess energy as a photon
None of these
a molecule returns to the electronic ground state from an excited triplet state by losing it's excess energy as a photon

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