Electrical Machines Which of the following voltage regulator is preferred for providing large values of load current? Transistor shunt regulator. Transistor series regulator. None of these Zener diode shunt regulator. Transistor shunt regulator. Transistor series regulator. None of these Zener diode shunt regulator. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 3-φ alternator has negligible stator resistance. A short circuit test is conducted on this alternator. At a particular speed, a field current of If1 is required to drive the rated armature current. If the speed of the alternator is reduced to half, the field current required to maintain rated armature current Would be equal to If1. Cannot be predicted due to insufficient data. Woud be equal to 2If1. Would be equal to If1/2. Would be equal to If1. Cannot be predicted due to insufficient data. Woud be equal to 2If1. Would be equal to If1/2. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines 1 KVA, 230 V, 50 Hz, single phase transformer has an eddy current loss of 30 watts. The eddy current loss when the transformer is excited by a dc source of same voltage will be zero watt less than 30 W more than 30 W 30 W zero watt less than 30 W more than 30 W 30 W ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Which of the following DC Motor uses 4-point starter? DC compound motor. DC shunt motor with field weaking control. DC series motor. DC shunt motor with armature resistance. DC compound motor. DC shunt motor with field weaking control. DC series motor. DC shunt motor with armature resistance. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Which motor cannot be started on no load? series motors shunt motors cumulative compound motors both B and C series motors shunt motors cumulative compound motors both B and C ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a 3 - Φ IM with line frequency f1 and winding factor kw1 and kw2 for stator and rotor respectively the ratio of per phase stator winding emf E1 to per phase rotor winding emf E2 at standstill is given by E1 / E2 = f1kw1 / f2kw2. E1 / E2 = 1. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = N1 / N2. E1 / E2 = f1kw1 / f2kw2. E1 / E2 = 1. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = N1 / N2. ANSWER DOWNLOAD EXAMIANS APP
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