JAVA Interfaces and Abstract Classes Which of the following statements regarding abstract classes are true? An abstract class can be used as a data type. A subclass can override a concrete method in a superclass to declare it abstract. An abstract class can be extended. A subclass of a non-abstract superclass can be abstract. All of these An abstract class can be used as a data type. A subclass can override a concrete method in a superclass to declare it abstract. An abstract class can be extended. A subclass of a non-abstract superclass can be abstract. All of these ANSWER DOWNLOAD EXAMIANS APP
JAVA Interfaces and Abstract Classes What happens if the following program is compiled and executed?interface MyInterface{ void display();}interface MySubInterface extends MyInterface{ void display();}public class Test implements MySubInterface{ public void display(){ System.out.print("Welcome to Examveda."); } public static void main(String args[]){ Test t = new Test(); t.display(); }} The code will compile and execute successfully showing the output Welcome to Examians. The code will lead to a compilation error as declaration of the display method has been provided in two interface. The code will lead to a compilation error as the display method is not declared as abstract. None of these The code will lead to a compilation error due to public modifier while declaring the display method. The code will compile and execute successfully showing the output Welcome to Examians. The code will lead to a compilation error as declaration of the display method has been provided in two interface. The code will lead to a compilation error as the display method is not declared as abstract. None of these The code will lead to a compilation error due to public modifier while declaring the display method. ANSWER DOWNLOAD EXAMIANS APP
JAVA Interfaces and Abstract Classes What will be the output?interface A{public void method();}class One{public void method(){System.out.println("Class One method");}}class Two extends One implements A{public void method(){System.out.println("Class Two method");}}public class Test extends Two{public static void main(String[] args){A a = new Two();a.method();}} Compilation Error will print Class One method will print Class Two method compiles fine but print nothing None of these Compilation Error will print Class One method will print Class Two method compiles fine but print nothing None of these ANSWER DOWNLOAD EXAMIANS APP
JAVA Interfaces and Abstract Classes interface Base{ boolean m1 (); byte m2(short s);}which two code fragments will compile?1. interface Base2 implements Base {}2. abstract class Class2 extends Base { public boolean m1(){ return true; }}3. abstract class Class2 implements Base {}4. abstract class Class2 implements Base { public boolean m1(){ return (7 > 4); }}5. abstract class Class2 implements Base { protected boolean m1(){ return (5 > 7) }} 1 and 2 3 and 4 2 and 3 4 and 5 1 and 3 1 and 2 3 and 4 2 and 3 4 and 5 1 and 3 ANSWER DOWNLOAD EXAMIANS APP
JAVA Interfaces and Abstract Classes What will be the output for the below code ?public interface TestInf{ int i =10;}public class Test{ public static void main(String... args){ TestInf.i=12; System.out.println(TestInf.i); }} Runtime Exception 12 Compile with error None of these 10 Runtime Exception 12 Compile with error None of these 10 ANSWER DOWNLOAD EXAMIANS APP
JAVA Interfaces and Abstract Classes Given the following piece of code:public interface Guard{ void doYourJob();}abstract public class Dog implements Guard{ }which of the following statements is correct? This code will not compile, because in the declaration of class Dog we must use the keyword extends instead of implements. This code will not compile, because method doYourJob() in interface Guard must be defined abstract. This code will not compile, because class Dog must implement method doYourJob() from interface Guard. This code will compile without any errors. This code will not compile, because in the declaration of class Dog we must use the keyword extends instead of implements. This code will not compile, because method doYourJob() in interface Guard must be defined abstract. This code will not compile, because class Dog must implement method doYourJob() from interface Guard. This code will compile without any errors. ANSWER DOWNLOAD EXAMIANS APP
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