Irrigation Engineering Which of the following methods of applying water may be used on rolling land ? check flooding boarder flooding free flooding furrow flooding check flooding boarder flooding free flooding furrow flooding ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering As per Lacey’s theory, the silt factor is not related to average particle size directly proportional to average par¬ticle size inversely proportional to average par¬ticle size directly proportional to square root of average particle size not related to average particle size directly proportional to average par¬ticle size inversely proportional to average par¬ticle size directly proportional to square root of average particle size ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering The duty is largest at the head of a main canal same at all places at the head of water course on the field at the head of a main canal same at all places at the head of water course on the field ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering If H and d are the water depth and drop in the bed level at a Sarda fall, the width B of the trapezoidal crest, is given by B = 0.44 √(H + d) B = 0.22 √(H + d) B = 0.55 √(H + d) B = 0.33 √(H + d) B = 0.44 √(H + d) B = 0.22 √(H + d) B = 0.55 √(H + d) B = 0.33 √(H + d) ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering Silt excluders are constructed on the river bed downstream of head regulator canal bed upstream of head regulator river bed upstream of head regulator canal bed downstream of head regulator river bed downstream of head regulator canal bed upstream of head regulator river bed upstream of head regulator canal bed downstream of head regulator ANSWER DOWNLOAD EXAMIANS APP
Irrigation Engineering According to Kennedy, the critical velocity (V₀) in meters in a channel is the mean velocity which keeps the channel free from silting or scouring. Its value is given by (where m is critical velocity ratio and D is the depth of the channel). V₀ = 0.55 mD0.54 V₀ = 0.84 mD0.64 V₀ = 0.55 mD0.64 V₀ = 0.84 mD0.54 V₀ = 0.55 mD0.54 V₀ = 0.84 mD0.64 V₀ = 0.55 mD0.64 V₀ = 0.84 mD0.54 ANSWER DOWNLOAD EXAMIANS APP
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