Power Systems Which of the following is/are the advantages of synchronous phase modifier over the shunt compensation? single unit can be used as both capacitance and inductor by adjusting the excitation both 1 and 2 smooth voltage regulation is possible by controlling excitation initial cost is low single unit can be used as both capacitance and inductor by adjusting the excitation both 1 and 2 smooth voltage regulation is possible by controlling excitation initial cost is low ANSWER DOWNLOAD EXAMIANS APP
Power Systems For load flow studies, What are the quantities specified at load bus are P and Q V and δ P and V δ and Q P and Q V and δ P and V δ and Q ANSWER DOWNLOAD EXAMIANS APP
Power Systems Which of the following is/are the disadvantages of phase modifiers? It requires more maintenance because of running equipment All of these It consumes both active and reactive power Initial cost of synchronous phase modifier is higher It requires more maintenance because of running equipment All of these It consumes both active and reactive power Initial cost of synchronous phase modifier is higher ANSWER DOWNLOAD EXAMIANS APP
Power Systems Nuclear fission means graphite. combination of two light nuclei. breaking up of nuclear of heavy atoms into nearly equal parts. moderator. graphite. combination of two light nuclei. breaking up of nuclear of heavy atoms into nearly equal parts. moderator. ANSWER DOWNLOAD EXAMIANS APP
Power Systems Which of the following statement is/are true?Zn The neutral grounding impedance Zn appears as 3Zn in zero sequence equivalent circuit The neutral grounding impedance Zn appears as Zn in zero sequence equivalent circuit nether 1 nor 2 both 1 and 2 The neutral grounding impedance Zn appears as 3Zn in zero sequence equivalent circuit The neutral grounding impedance Zn appears as Zn in zero sequence equivalent circuit nether 1 nor 2 both 1 and 2 ANSWER DOWNLOAD EXAMIANS APP
Power Systems The power generated by two plants are; P1 = 50 MW, P2 = 40 MW. If the loss coefficients are B11 = 0.001, B22 = 0.0025 and B12 = -0.0005, then power loss will be 4.5 MW 6.5 MW 8.5 MW 5.5 MW 4.5 MW 6.5 MW 8.5 MW 5.5 MW ANSWER DOWNLOAD EXAMIANS APP
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