Analog Electronics When VGS = 0 V, a JFET is saturated. cut off. an open switch. an analog device. saturated. cut off. an open switch. an analog device. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The current gain of a pnp transistor is near zero. the ratio of collector current to emitter current. the collector current divided by the emitter current. the negative of the npn current gain. near zero. the ratio of collector current to emitter current. the collector current divided by the emitter current. the negative of the npn current gain. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The opamp can amplify neither AC not DC signals. both AC and DC signals. AC signals only. DC signals only. neither AC not DC signals. both AC and DC signals. AC signals only. DC signals only. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The voltage follower has a closed - loop voltage gain of unity. small open - loop voltage gain. large closed - loop output impedance. closed - loop bandwidth of zero. closed - loop voltage gain of unity. small open - loop voltage gain. large closed - loop output impedance. closed - loop bandwidth of zero. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics In a normally biased npn transistor, the electrons in the emitter have enough energy to overcome the barrier potential of the base - emitter junction. collector - base junction. recombination path. base - collector junction. base - emitter junction. collector - base junction. recombination path. base - collector junction. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics An npn BJT has gm=38mA/v, cµ =10¯14 F, cπ =10¯13F and DC current gain β0=90.For this transistor fT & fβ are fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz ANSWER DOWNLOAD EXAMIANS APP
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