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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 When the supply to the excitation fails, the synchronous generator acts like a/an

Induction motor
Synchronous generator
Induction generator
Synchronous motor

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SSC JE Electrical 2019 with solution SET-1
 The below symbol which is used in single line diagrams represents

Power transformer
Current transformer
Circuit breaker
Potential transformer

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SSC JE Electrical 2019 with solution SET-1
 Find the mutual inductance between two ideally coupled coils of 2H and 8H

2 H
4 H
8 H
16 H

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Mutual inductance between the two coils is K = √L1.L2
K = √2 × 8
k = √16
k = 4 H
 

SSC JE Electrical 2019 with solution SET-1
 At f =  _____R – L – C series circuit operates at unity power factor

1 ⁄ RLC
1/2π√LC
1 ⁄ LC
1/RC

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SSC JE Electrical 2019 with solution SET-1
 A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is

0.4 V
−2.5 V
−4 V
−10 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given
Inductance L = 2 H
Rate of change of current di/dt = 5 A/sec
Self induced EMF = − (Rate of change of current × Inductance) = −L(di/dt)
= −(5 × 2) = −10V
 

SSC JE Electrical 2019 with solution SET-1
______ Opposes the change in circuit voltage

Capacitance
Inductance
Resistance
Inductive reactance

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