Applied Mechanics and Graphic Statics When a body in equilibrium undergoes an infinitely small displacement, work imagined to be done, is known as Imaginary work None of these Negative work Virtual work Imaginary work None of these Negative work Virtual work ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Newton's law of Collision of elastic bodies states that when two moving bodies collide each other, their velocity of separation Is inversely proportional to their velocity of approach Is directly proportional to their velocity of approach Is equal to the sum of their velocities of approach Bears a constant ratio to their velocity of approach Is inversely proportional to their velocity of approach Is directly proportional to their velocity of approach Is equal to the sum of their velocities of approach Bears a constant ratio to their velocity of approach ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A weight ‘W’ is suspended at the free end of a light member hinged to a vertical wall. If the angle of inclination of the member with the upper wall is θ°, the force introduced in the member, is W cos θ W cosec θ W sec θ W sin θ W cos θ W cosec θ W sec θ W sin θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two parallel forces 20 kg and 15 kg act. In order that the distance of the resultant from 20 kg force may be the same as that of the former resultant was from 15 kg, the 20 kg force is diminished by 8.75 kg 10.5 kg 6.25 kg 5.5 kg 8.75 kg 10.5 kg 6.25 kg 5.5 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The reaction between the sphere and the wall of the arrangement made is 105.5 kg 108.5 kg 110 kg 102.5 kg 105.5 kg 108.5 kg 110 kg 102.5 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Maximum efficiency of a screw jack for the angle of friction θ, is (1 - sin θ)/sin θ (1 + sin θ)/(1 - sin θ) (1 - sin θ)/(1 + sin θ) sin θ/(1 + sin θ) (1 - sin θ)/sin θ (1 + sin θ)/(1 - sin θ) (1 - sin θ)/(1 + sin θ) sin θ/(1 + sin θ) ANSWER DOWNLOAD EXAMIANS APP
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