JAVA Threads
What will happen when you attempt to compile and run the following code?class A implements Runnable{ public void run(){ System.out.println("run-A"); }}1. public class Test{2. public static void main(String argv[]){3. A a = new A();4. Thread t = new Thread(a);5. System.out.println(t.isAlive());6. t.start();7. System.out.println(t.isAlive());8. }9. }

None of these
true run-A true
false run-A true
Compilation fails due to an error on line 7
false run-A false

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JAVA Threads
Given the code. What will be the result?public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); }}

An exception is thrown at runtime.
"BeginEndRun" is printed.
"BeginRunEnd" is printed.
"BeginEnd" is printed.
Compilation fails.

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JAVA Threads
What notifyAll() method do?

None of these
Wakes up all threads that are waiting on this object's monitor
Wakes up all threads that are not waiting on this object's monitor
Wakes up one threads that are waiting on this object's monitor

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

Output order is not guaranteed
A A A A B B B B
Compilation succeed but Runtime Exception
None of these
A B A B A B A B

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