JAVA Threads
Analyze the following code:public class Test implements Runnable{ public static void main(String[] args){ Test t = new Test(); t.start(); } public void run() { }}

The program compiles and runs fine.
The program compiles, but it does not run because the run() method is not implemented.
The program does not compile because the start() method is not defined in the Test class.
The program compiles, but it does not run because the start() method is not defined.

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JAVA Threads
Given the code. What will be the result?public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); }}

An exception is thrown at runtime.
"BeginEnd" is printed.
Compilation fails.
"BeginRunEnd" is printed.
"BeginEndRun" is printed.

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JAVA Threads
What is the output for the below code ?class A implements Runnable{ public void run(){ System.out.println(Thread.currentThread().getName()); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.setName("good");6. t.start();7. }8. }

Compilation succeed but Runtime Exception
None of these
Compilation fails with an error at line 5
good
null

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

Compilation succeed but Runtime Exception
Output order is not guaranteed
A B A B A B A B
None of these
A A A A B B B B

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