JAVA Threads
Analyze the following code:public class Test implements Runnable{ public static void main(String[] args){ Test t = new Test(); t.start(); } public void run() { }}

The program compiles, but it does not run because the run() method is not implemented.
The program does not compile because the start() method is not defined in the Test class.
The program compiles, but it does not run because the start() method is not defined.
The program compiles and runs fine.

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JAVA Threads
What is the output for the below code ?public class Test extends Thread{ public static void main(String argv[]){ Test t = new Test(); t.run(); } public void start(){ for(int i = 0; i < 10; i++){ System.out.println("Value of i = " + i); } }}

Clean compile but no output at runtime
A run time error indicating that no run method is defined for the Thread class
None of these
A compile time error indicating that no run method is defined for the Thread class
Clean compile and at run time the values 0 to 9 are printed out

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JAVA Threads
What will happen when you attempt to compile and run the following code?class A implements Runnable{ public void run(){ System.out.println("run-A"); }}1. public class Test{2. public static void main(String argv[]){3. A a = new A();4. Thread t = new Thread(a);5. System.out.println(t.isAlive());6. t.start();7. System.out.println(t.isAlive());8. }9. }

false run-A true
Compilation fails due to an error on line 7
None of these
true run-A true
false run-A false

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

A A A A B B B B
None of these
Output order is not guaranteed
Compilation succeed but Runtime Exception
A B A B A B A B

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