JAVA Threads
What will be output of the following program code?public class Test implements Runnable{ public void run(){ System.out.print("go"); } public static void main(String arg[]) { Thread t = new Thread(new Test()); t.run(); t.run(); t.start(); }}

"gogogo" is printed
An exception is thrown at runtime.
"gogo" is printed
Compilation fails.
"go" is printed

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JAVA Threads
Analyze the following code:public class Test implements Runnable{ public static void main(String[] args){ Test t = new Test(); t.start(); } public void run() { }}

The program compiles and runs fine.
The program does not compile because the start() method is not defined in the Test class.
The program compiles, but it does not run because the start() method is not defined.
The program compiles, but it does not run because the run() method is not implemented.

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JAVA Threads
What will happen when you attempt to compile and run the following code?1. public class Test extends Thread{2. public static void main(String argv[]){3. Test t = new Test();4. t.run();5. t.start();6. }7. public void run(){8. System.out.println("run-test");9. }10. }

run-test
Compilation fails due to an error on line 4
None of these
Compilation fails due to an error on line 7
run-test run-test

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JAVA Threads
What will happen after compiling and running following code?class A implements Runnable{ public void run(){ System.out.println("run-a"); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.start();6. t.start();7. }8. }

None of these
run-a
Compilation fails with an error at line 6
Compilation succeed but Runtime Exception
run-a run-a

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

None of these
Output order is not guaranteed
A B A B A B A B
A A A A B B B B
Compilation succeed but Runtime Exception

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