JAVA Threads
What will be output of the following program code?public class Test implements Runnable{ public void run(){ System.out.print("go"); } public static void main(String arg[]) { Thread t = new Thread(new Test()); t.run(); t.run(); t.start(); }}

An exception is thrown at runtime.
"go" is printed
"gogogo" is printed
"gogo" is printed
Compilation fails.

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JAVA Threads
What is the output for the below code ?class A implements Runnable{ public void run(){ System.out.println(Thread.currentThread().getName()); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.setName("good");6. t.start();7. }8. }

null
None of these
good
Compilation fails with an error at line 5
Compilation succeed but Runtime Exception

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JAVA Threads
What will happen after compiling and running following code?class A implements Runnable{ public void run(){ System.out.println("run-a"); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.start();6. t.start();7. }8. }

run-a
run-a run-a
Compilation fails with an error at line 6
None of these
Compilation succeed but Runtime Exception

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JAVA Threads
What will be the output of the following program code?public class Test implements Runnable{ public static void main(String[] args){ Thread t = new Thread(this); t.start(); } public void run(){ System.out.println("test"); }}

None of these
The program does not compile because this cannot be referenced in a static method.
The program compiles and runs fine and displays test on the console.
The program compiles fine, but it does not print anything because t does not invoke the run() method

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

None of these
A A A A B B B B
Compilation succeed but Runtime Exception
A B A B A B A B
Output order is not guaranteed

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