JAVA Threads
What will be the output?class One extends Thread{public void run(){for(int i=0; i<2; i++){System.out.print(i);}}}public class Test{public static void main(String args[]){Test t = new Test();t.call(new One());} public void call(One o){o.start();}}

0 1
Compilation Error
None of these
0 0

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JAVA Threads
What will happen when you attempt to compile and run the following code?1. public class Test extends Thread{2. public static void main(String argv[]){3. Test t = new Test();4. t.run();5. t.start();6. }7. public void run(){8. System.out.println("run-test");9. }10. }

None of these
Compilation fails due to an error on line 7
run-test run-test
run-test
Compilation fails due to an error on line 4

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JAVA Threads
What will be the output after compiling and executing the following code?public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); }}

Compilation fails.
"BeginEndRun" is printed.
"BeginRunEnd" is printed.
"BeginEnd" is printed.
An exception is thrown at runtime.

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

A A A A B B B B
None of these
A B A B A B A B
Output order is not guaranteed
Compilation succeed but Runtime Exception

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