JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

Output order is not guaranteed
A A A A B B B B
None of these
A B A B A B A B
Compilation succeed but Runtime Exception

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JAVA Threads
Given the code. What will be the result?public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); }}

"BeginEnd" is printed.
"BeginEndRun" is printed.
Compilation fails.
"BeginRunEnd" is printed.
An exception is thrown at runtime.

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JAVA Threads
What will happen after compiling and running following code?class A implements Runnable{ public void run(){ System.out.println("run-a"); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.start();6. t.start();7. }8. }

run-a
Compilation fails with an error at line 6
Compilation succeed but Runtime Exception
run-a run-a
None of these

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JAVA Threads
Analyze the following code:public abstract class Test implements Runnable{ public void doSomething() { };}

The program will not compile because it does not implement the run() method.
The program compiles fine.
None of these
The program will not compile because it does not contain abstract methods.

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