JAVA Threads
What will be the output?class A extends Thread{ public void run(){ for(int i=0; i<2; i++){ System.out.println(i); } }}public class Test{ public static void main(String argv[]){ Test t = new Test(); t.check(new A(){}); } public void check(A a){ a.start(); }}

0 0
None of these
Compilation error, class A has no start method
0 1
Compilation succeed but runtime exception

ANSWER DOWNLOAD EXAMIANS APP

JAVA Threads
Analyze the following code:public class Test implements Runnable{ public static void main(String[] args){ Test t = new Test(); } public Test(){ Thread t = new Thread(this); t.start(); } public void run(){ System.out.println("test"); }}

The program has a compilation error because t is defined in both the main() method and the constructor Test().
The program compiles and runs and displays nothing.
The program compiles fine, but it does not run because you cannot use the keyword this in the constructor.
The program compiles and runs and displays test.

ANSWER DOWNLOAD EXAMIANS APP

JAVA Threads
What will happen when you attempt to compile and run the following code?1. public class Test extends Thread{2. public static void main(String argv[]){3. Test t = new Test();4. t.run();5. t.start();6. }7. public void run(){8. System.out.println("run-test");9. }10. }

None of these
run-test
Compilation fails due to an error on line 7
Compilation fails due to an error on line 4
run-test run-test

ANSWER DOWNLOAD EXAMIANS APP

JAVA Threads
Analyze the following code:public class Test implements Runnable{ public static void main(String[] args){ Test t = new Test(); t.start(); } public void run() { }}

The program compiles, but it does not run because the run() method is not implemented.
The program does not compile because the start() method is not defined in the Test class.
The program compiles and runs fine.
The program compiles, but it does not run because the start() method is not defined.

ANSWER DOWNLOAD EXAMIANS APP

JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

A A A A B B B B
None of these
Compilation succeed but Runtime Exception
Output order is not guaranteed
A B A B A B A B

ANSWER DOWNLOAD EXAMIANS APP

JAVA Threads
What will happen after compiling and running following code?class A implements Runnable{ public void run(){ System.out.println("run-a"); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.start();6. t.start();7. }8. }

Compilation fails with an error at line 6
None of these
Compilation succeed but Runtime Exception
run-a run-a
run-a

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON JAVA Threads