JAVA Threads
What notifyAll() method do?

None of these
Wakes up all threads that are waiting on this object's monitor
Wakes up one threads that are waiting on this object's monitor
Wakes up all threads that are not waiting on this object's monitor

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JAVA Threads
Given the code. What will be the result?public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); }}

Compilation fails.
"BeginEndRun" is printed.
An exception is thrown at runtime.
"BeginEnd" is printed.
"BeginRunEnd" is printed.

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JAVA Threads
Analyze the following code:public class Test implements Runnable{ public static void main(String[] args){ Test t = new Test(); } public Test(){ Thread t = new Thread(this); t.start(); } public void run(){ System.out.println("test"); }}

The program has a compilation error because t is defined in both the main() method and the constructor Test().
The program compiles fine, but it does not run because you cannot use the keyword this in the constructor.
The program compiles and runs and displays test.
The program compiles and runs and displays nothing.

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JAVA Threads
What will happen when you attempt to compile and run the following code?1. public class Test extends Thread{2. public static void main(String argv[]){3. Test t = new Test();4. t.run();5. t.start();6. }7. public void run(){8. System.out.println("run-test");9. }10. }

run-test
Compilation fails due to an error on line 4
Compilation fails due to an error on line 7
run-test run-test
None of these

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

A B A B A B A B
None of these
A A A A B B B B
Compilation succeed but Runtime Exception
Output order is not guaranteed

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