Electrical Machines What is the mechanical power developed by a DC series motor is maximum? Back emf is equal to half the applied voltage. None of above. Back emf is equal to applied voltage. Back emf is equal to zero. Back emf is equal to half the applied voltage. None of above. Back emf is equal to applied voltage. Back emf is equal to zero. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The direction of rotation of conductor of a DC motor can be determined by Fleming's right hand rule. Fleming's left hand rule. Lenz's law. Ampere law. Fleming's right hand rule. Fleming's left hand rule. Lenz's law. Ampere law. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines If a transformer has turns ratio K, the primary and secondary current are I1 and I2 respectively and magnetizing current and core loss component of no load current Iμ and Iw respectively, then I1 = KI2 + Iw + Iμ.ok I1 = KI2 + Iμ. I1 = KI2. I1 = KI2 + Iw. I1 = KI2 + Iw + Iμ.ok I1 = KI2 + Iμ. I1 = KI2. I1 = KI2 + Iw. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines High starting torque and low starting current is the advantage of stepper motor. squirrel cage induction motor. hysteresis motor. slip ring induction motor. stepper motor. squirrel cage induction motor. hysteresis motor. slip ring induction motor. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines If iron loss and full load copper loss of any transformer are denoted by Pi and Pc, then the load corresponding to maximum efficiency is given by (Pi / Pc)1.6 × full Load. (Pi / Pc) × full Load. (Pi / Pc)2 × full Load. (Pi / Pc)0.5 × Full Load. (Pi / Pc)1.6 × full Load. (Pi / Pc) × full Load. (Pi / Pc)2 × full Load. (Pi / Pc)0.5 × Full Load. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A commutator with a diameter of 50 cm rotating at 1000 rpm. For a brush width of 1.5 cm, find the time of commutation in ms. 0.649. 0.443. 0.512. 0.573. 0.649. 0.443. 0.512. 0.573. ANSWER DOWNLOAD EXAMIANS APP
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